Calculate the number of so2 molecules formed when 14 s8 molecules and 184 o2 molecules react

112 molecules are formed from the reaction

Explanation:

Let's make the reaction:

S₈ + 8O₂  → 8SO₂

1 mol of S₈ reacts with 8 moles of O₂ to produce 8 moles of sulfur dioxide

Let's determine the moles ( amount of molecules / NA)

14 / 6.02x10²³ = 2.32x10⁻²³ mol of S

184 / 6.02x10²³ = 3.05x10⁻²² mol of O₂

As ratio is 1:8, the limiting reactant would be the sulfur. It's obviouly I do not have enough the amount of molecules.

8 mol of O₂ need 1 mol of S₈

3.05x10⁻²² mol of O₂ would need (3.05x10⁻²² / 8) = 3.81ₓ10²¹

Now, that we get the limiting, we can work with the reaction

1 mol of S₈ produce 8 mol of dioxide

Then, 2.32x10⁻²³ mol of S will produce (2.32x10⁻²³ . 8) = 1.85x10⁻²² moles of SO₂

Let's convert the moles in, amount of molecules (mol . NA)

1.85x10⁻²² mol . 6.02x10²³ = 112 molecules

c. 75.7

i think that is the right