If 21 ml of gas is subjected to a temperature change from 10.0°c to 120°c and a pressure change from 1.0 atm to 15 atm, the new volume is: (be sure to use the correct number of significant figures.) 1.9 ml 1.0 ml 0.53 ml 440 ml

 The  new volume is  1.9  ml

calculation

The new   volume  is  calculated using the   combined gas  equation

that is  P1V1/T1 = P2V2/T2  where

P1= 1.0 atm

V1= 21   ml

T1 = 10.0 c  into kelvin = 10 + 273 = 283 k

P2 = 15 atm

V2=? Ml

T2 = 120 c  into kelvin = 120 +273 = 393 K

make V2  the subject of the   formula by  multiplying  both side  by T2/P2

V2=T2P1v1 / P2T1

V2=[(393 k  x 1.0 atm  x 21  ml) / (15 atm x 283 K)]  = 1.9  Ml

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