If you take 15.0 ul of a solution with a concentration of 0.0100 m and you dilute it to a total volume of 170.0 ul, what will be the new concentration?

8.82x10⁻³ M will be the new concentration

Explanation:

Let's apply the dilution formula.

C₁ . V₁ = C₂ . V₂

15 μL . 0.01M = 170 μL . C₂

(15 μL . 0.01M) /170 μL = C₂ → 8.82x10⁻³ M

the correct answer is boyle

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml