Acopper cube with a mass of 100 grams is heated in a boiling water bath to 100.0 celsius. the cube is removed from the bath and placed on a very large block of ice which is at a temperature of 0.00 celsius. what is the maximum mass of ice that could conceivably be melted by the heat exchange, assuming all the thermal energy is used to melt the ice? the specific heat of copper is 0.39 j/g-c and the enthalpy of fusion for water is 334 j/g.

The copper cube has a mass of 11.68 grams

Explanation:

Step 1: Data given

Mass of the copper cube = 100 grams

Temperature of water = 100°C

Temperature of ice = 0°C

Specific heat of copper = 0.39J/g°C

Enthalpy of fusion of water = 334 J/g

Step 2:  Calculate the energy for cooling the copper

energy in the copper as it cools from 100º to 0º = 0.39 J/g°C * 100g *100°C = 3900 J

Step 3: Calculate the mass of the copper cube

3900 J / 334 J/g = 11.68 grams

The copper cube has a mass of 11.68 grams

M = 3900/334 = 11.68 g

change is 3900 J

assuming that your periodic table has eighteen columns, you should highlight   the four elements in the third column from the left of the table.

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