Exposing a 250 ml sample of water at 20.∘c to an atmosphere containing a gaseous solute at 27.59 kpa resulted in the dissolution of 4.51×10−3 g of the solute. use henry's law to determine the solubility of this gaseous solute when its pressure is 79.39 kpa.

Answer : The solubility of this gaseous solute will be,

Explanation :

First we have to calculate the concentration of solute.

Now we have to calculate the Henry's law constant.

Using Henry's law :

where,

C = concentration of solute =

p = partial pressure = 27.59 kPa

= Henry's law constant = ?

Now put all the given values in the above formula, we get:

Now we have to calculate the solubility of this gaseous solute when its pressure is 79.39 kPa.

Therefore, the solubility of this gaseous solute will be,

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.