Identify the oxidation number of the highlighted carbon atoms in each of the molecules.

a. in molecule a a central carbon atom is bonded to two c h 3 groups and an o atom through a double bond.
b. the central carbon atom is highlighted.
c. in molecule b, a central carbon atom is bonded to two c h 3 groups, an o h group, and an h atom.
d. the central carbon atom is highlighted.

A) Oxidation state of carbon is +2

B) Oxidation state of carbon is 0

Explanation:

In the first question  , the compound is propanone.

While assigning oxidation states ,

We must see to that , the electrons in the bond moves towards the most electronegative atom.If they are equally electronegative , each of them gets 0 oxidation state respectively.And if there is one bond , the oxidation state obtained by the electronegative atom is -1 and the other is +1.The order of electronegativity is as follows :

Thus always gets -1 and always gets +1 in these two compounds.The carbon - carbon bond will give 0 oxidation state.

A) According to these rules the Oxidation state of carbon is +2

B) According to these rules the Oxidation state of carbon is 0

Diagram attached below The direction of the arrows in the diagram represents the movement of electron