Ahorizontal tube carrying hot water has a surface temperature of 355.4 k and an outside diameter

of 25.4 mm. the tube is exposed to room air at 294.3 k. what is the natural convection heat loss

for a 1 m length of the pipe?

The natural convection heat loss is 185.5 W

Explanation:

The equation for convection heat loss is:

Q/t = k*A*(T1-T2)/d

in which: Q/t is the convection heat loss, k is 0.6 W/mK for water, A is the are of the tube which corresponds to (πd^2)/4. d= 25.4 mm or 0.0254 m. The area is 5.06 m2. The difference in temperature is given by the problem: 355.4 K - 294.3 K. d for the convection heat loss is the thickness of the barrier which is 1 m of the length of the pipe.

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