What is the molarity of a naoh solution if 25.00ml is required to neutralize 40.00ml of a 1.50m solution of h2so4

V( H₂SO₄) = 40.00 mL in liters = 40.00 / 1000 = 0.04 L 
M(H₂SO₄) = 1.50 M

V(NaOH) = 25.00mL = 25.00/ 1000 = 0.025 L 
M(NaOH) = ?

number of moles H₂SO₄ :

n = M x V

n = 1.50 x  0.04

n = 0.06 moles of H₂SO₄

H₂SO₄(aq) + 2 NaOH(aq) = Na₂SO₄(aq) + 2 H₂O(l)

1 mole H₂SO₄ 2 mole NaOH
0.06 moles H₂SO₄ ?

moles = 0.06 * 2 / 1

= 0.12 moles of NaOH

M(NaOH) = n / V

M = 0.12 / 0.025  

= 4.8 M

hope this helps!

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