Agas mixture has a total pressure of 0.51 atm and consists of he and ne. if the partial pressure of he in the mixture is 0.32 atm, what is the partial pressure of the ne in the mixture? enter your answer in the provided box. atm

Explanation:

Relation between total pressure and mole fraction is as follows.

where,     = partial pressure of gas 1

                = mole fraction of gas 1

                = total pressure of the gases

Also,  it is known that = 1

or,              

It is given that total pressure of gas mixture is 0.51 atm and partial pressure of helium is 0.32 atm.

Hence, calculate the mole fraction of helium gas present in the given mixture as follows.

                0.32 atm =

                    = 0.63

As, = 1

so,            

                               = 1 - 0.63

                               = 0.37

Hence, calculate the partial pressure of Ne as follows.

                       0.3084 atm =

                                        = 0.834 atm

Thus, we can conclude that the partial pressure of the Ne in the mixture is 0.834 atm.

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answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.