Question 6 1.75 pts the following reaction 2h2s(g)=2h2(g)+s2(g), kc=1.625x10-7 at 800°c is carried out at the same temperature with the following initial concentrations: [h, s]=0.162m, [h2]=0.184 m, and [s2]=0.00 m. find the equilibrium concentration of s2. express the molarity to three significant figures. answer in units of nm.

[S₂] = 1.27×10⁻⁷ M

Explanation:

2 H₂S(g) ⇄ 2 H₂(g) + S₂(g), Kc=1,625x10⁻⁷

The equation of this reaction is:

1,625x10⁻⁷ =

The equilibrium concentrations are:

[H₂S] = 0,162 - 2x

[H₂] = 0,184 + 2x

[S₂] = x

Replacing:

1,625x10⁻⁷ =

Solving:

4x³ + 0,736x² + 0,033856x - 4,3x10⁻⁹

x = 1.27×10⁻⁷

Thus, concentration of S₂ is:

[S₂] = 1.27×10⁻⁷ M

the answer is na (sodium)

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