You are given 50.0 ml of 1.50 m hno3. how many ml of 0.81 m naoh are needed to neutralize it?

V(HNO₃) = 50.0 mL in liters = 50.0 /1000 =0.05 L
M(HNO₃) = 1.50 M

Number of moles HNO₃ :

n = M x V

n = 1.50 x 0.05

n = 0.075 moles of HNO₃

HNO₃ + NaOH = H₂O + NaNO₃

1 mole HNO₃ ---1 mole NaOH
0.075 moles HNO₃ ?

moles NaOH = 0.075 * 1 / 1

 = 0.075 moles of NaOH

V ( NaOH ) :

M = n / V

0.81 = 0.075 / V

V = 0.075 / 0.81

V = 0.0925 L or  92.5 mL 

hope this helps!

Ithink it's carbonic acid

Firstly, the water in the dams hold gravitational potential energy as they are above ground level. the gravitational potential energy is then transferred to kinetic energy as it falls, spinning the turbinethe turbine then spins the generator, which is a large magnet surrounded by metal coils. by doing this, the generator generates electricity. in this action, the energy transfer taken place is kinetic to electric energy