Write the smaller solution first, and the larger solution second. h(x)=-5x^2 +180h(x)=−5x 2 +180

x = -6,6

Step-by-step explanation:

h(x)=−5x^2 +180

Assuming you want to find the zero's

0 =−5x 2 +180

Subtract 180 from each side

0-180=−5x^2 +180-180

-180 = -5x^2

Divide each side by -5

-180/-5 = -5x^2/-5

36 = x^2

Take the square root of each side

±sqrt(36) = sqrt(x^2)

±6 = x

x = -6,6

-6, 6

Step-by-step explanation:

h(x) = -5x² + 180

-5x² + 180 = 0

x² = 36

x = -6, 6

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

4444444444444 i think