2) show the calculation of kc for the following reaction if an initial reaction mixture of 0.800 mole of co and 2.40 mole of h2 in a 8.00 liter container forms an equilibrium mixture containing 0.309 mole of h2o and corresponding amounts of co, h2, and ch4.

Kc = 3.90

Explanation:

CO reacts with to form and . balanced reaction is:

No. of moles of CO = 0.800 mol

No. of moles of = 2.40 mol

Volume = 8.00 L

Concentration =

Concentration of CO =

Concentration of =

Initial            0.100      0.300             0   0

equi.            0.100 -x    0.300 - 3x     x    x

It is given that,

at equilibrium = 0.309/8.00 = 0.0386 M

So, at equilibrium CO = 0.100 - 0.0386 = 0.0614 M

At equilibrium = 0.300 - 0.0386 × 3 = 0.184 M

At equilibrium = 0.0386 M