The bus fare in a city is People who use the bus have the option of purchasing a monthly coupon book for With the coupon book, the fare is reduced to $0.50. How many times must someone use the bus so that the total monthly cost without the coupon book is the same as the total monthly cost with the coupon book? Express the total monthly cost to use the bus with a coupon book, f, as a function of the number of times in the month the bus is used, x. Then express the total monthly cost to use the bus without a coupon book, g, as a function of the number of times in the month the bus is used, x.

26 times

Step-by-step explanation:

The question has missing details. However, the given parameters are

Given

Without Coupon

Bus Fare = $2.00

With Coupon

Coupon = $39.00

Bus Fare = $0.50

Represent the number of fares with x

Without Coupon, cost of fares is

Cost = 2x

i.e.

f(x) = 2x

With Coupon, cost of fares is

Cost = 39 + 0.5x

i.e.

g(x) = 39 + 0.5x

To calculate when both fares will be equal, we must have:

f(x) = g(x)

2x = 39 + 0.5x

Collect like terms

2x - 0.5x = 39

1.5x = 39

Solve for x

x = 39/1.5

x = 26

This implies that, for both cost to be equal, the person must go 26 times

system of linear equation

step-by-step explanation:

as given in the data

a= 20 , b= -12

let us suppose that it is a straight line equation

now we know the formula for the system of linear equation

b= ma + c )

here m is slope of a straight line which is equal to formula

m=   (ii)

and here c is a constant

now putting the value of a and b in equation (ii)

m=

m=

putting the value of a,b and m in equation (i) gives us

-12 = + c

-12=-12 + c

adding 12 to both sides

-12 +12 = -12 +12 +c

0 =c

or c=0

as the value of the constant is zero which gives us that it is a linear equation and this order pair satisfies the system of linear equations.