What are the concentrations of hso4−, so42-, and h+ in a 0.35 m khso4 solution? (hint: h2so4 is a strong acid; ka for hso4− = 1.3 ✕ 10−

Answer : The concentration of , and are 0.29 M, 0.061 M and 0.061 M respectively.

Explanation :

First we have to calculate the concentration of

The dissociation of is:

As, 1 mole of gives 1 mole of

So, 0.35 M of gives 0.35 M of

Now we have to determine the concentration of and .

The dissociation of is:

Initial conc.      0.35           0       0

At eqm.          (0.35-x)        x        x

The expression of acid dissociation constant will be:

Now put all the given values in this expression, we get:

Thus, the concentration of = x = 0.061 M

The concentration of = x = 0.061 M

The concentration of = 0.35 - x = 0.35 - 0.061 = 0.29 M

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