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Mathematics, 28.09.2019 14:30 graciemonceret6213

Rachna has nickels, dimes, and quarters in her piggy bank. she has $4.65 altogether. she has three more quarters than dimes and twice as many nickels as quarters. how many quarters does rachna have?

a.8
b.11
c.22
d.41

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Answers: 1

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Answers

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Answer from: pearljammarow6ujs

The value of the coin times the number of coins equals the total value
so
0.05n + 0.10d + 0.25q = 4.65

the we are given that there are "three more quarters than dimes"
this translates to
q = d + 3
or
d = q - 3

then we are also given that there are "twice as many nickels as quarters"
this translates to
n = 2q

we plug d = q - 3 and n=2q
into the first equation and solve for q
0.05(2q) + 0.10(q-3) + 0.25q = 4.65

we distribute/multiply
0.10q + 0.10q - 0.30 + 0.25q = 4.65

then add like terms
0.45q - 0.30 = 4.65

then add 0.30 to both sides
0.45q = 4.95

then divide both sides by 0.45
and we get
q = 4.95/0.45 = 11

therefore there are 11 quarters

ansver

Answer from: Quest

x= 1

step-by-step explanation: convert 5\frac{11}{12}5

12

11

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

c

b

=

c

ac+b

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{5\times 12+11}{12}3.25+0.5x+1

3

1

+

6

5

x=

12

5×12+11

2 simplify 5\times 125×12 to 6060

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{60+11}{12}3.25+0.5x+1

3

1

+

6

5

x=

12

60+11

3 simplify 60+1160+11 to 7171

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{71}{12}3.25+0.5x+1

3

1

+

6

5

x=

12

71

4 simplify \frac{5}{6}x

6

5

x to \frac{5x}{6}

6

5x

3.25+0.5x+1\frac{1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+1

3

1

+

6

5x

=

12

71

5 convert 1\frac{1}{3}1

3

1

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

c

b

=

c

ac+b

3.25+0.5x+\frac{1\times 3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

3

1×3+1

+

6

5x

=

12

71

6 simplify 1\times 31×3 to 33

3.25+0.5x+\frac{3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

3

3+1

+

6

5x

=

12

71

7 simplify 3+13+1 to 44

3.25+0.5x+\frac{4}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

3

4

+

6

5x

=

12

71

8 simplify 3.25+0.5x+\frac{4}{3}+\frac{5x}{6}3.25+0.5x+

3

4

+

6

5x

to \frac{13.75}{3}+\frac{4x}{3}

3

13.75

+

3

4x

\frac{13.75}{3}+\frac{4x}{3}=\frac{71}{12}

3

13.75

+

3

4x

=

12

71

9 simplify \frac{13.75}{3}

3

13.75

to 4.5833334.583333

4.583333+\frac{4x}{3}=\frac{71}{12}4.583333+

3

4x

=

12

71

10 subtract 4.5833334.583333 from both sides

\frac{4x}{3}=\frac{71}{12}-4.583333

3

4x

=

12

71

−4.583333

11 simplify \frac{71}{12}-4.583333

12

71

−4.583333 to \frac{4}{3}

3

4

\frac{4x}{3}=\frac{4}{3}

3

4x

=

3

4

12 multiply both sides by 33

4x=\frac{4}{3}\times 34x=

3

4

×3

13 simplify \frac{4}{3}\times 3

3

4

×3 to \frac{12}{3}

3

12

4x=\frac{12}{3}4x=

3

12

14 simplify \frac{12}{3}

3

12

to 44

4x=44x=4

15 divide both sides by 44

x=1

ansver

Answer from: Quest

so the possibilities of the measurement of the side of the triangle are either it is longest side or not the longest side

when it is the longest side

s < 25 + 35s < 60

if it is not the longest side

35 < 25 + s10 < sso 10 < s < 60so the perimeter70 < p < 130

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