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Chemistry, 20.10.2019 11:30 nickthequick

Question 1(multiple choice worth 4 points) (04.05 lc) what is the oxidation number of manganese in mno41−? +3 +4 +7 +8 question 2(multiple choice worth 4 points) (04.05 lc) which of the following reactions could be used to power a battery because of the transfer of electrons? pb22+ + 2br− → pbbr cacl2 + 2naoh → ca(oh)2 + 2nacl koh + hcl → kcl + h2o zn + cu2+ → zn2+ + cu question 3(multiple choice worth 4 points) (04.05 mc) read the following chemical equation: 2al + 3br2 → 2albr3 which statement best identifies and describes the oxidizing agent in the reaction? al is the oxidizing agent because its oxidation number increases. al is the oxidizing agent because its oxidation number decreases. br2 is the oxidizing agent because its oxidation number increases. br2 is the oxidizing agent because its oxidation number decreases. question 4(multiple choice worth 4 points) (04.05 mc) in which of the following reactions is chlorine (cl) oxidized? br2 + 2cl− → cl2 + 2br− cl2 + 2e− → 2cl− 2clo3− + 12h+ → cl2 + 6h2o 2na + cl2 → 2nacl question 5(multiple choice worth 4 points) (04.05 mc) the diagram shows the setup of an experiment. a few observations of the experiment are listed in the table below the diagram. a beaker filled three-fourths with a liquid labeled colorless silver nitrate solution is shown. a small strip is shown inside the beaker. the strip is labeled copper strip. the title of the image is experimental setup. experimental observations observation description 1 solution turned blue 2 gray particles were deposited on the edge of the strip which of the following is the correct explanation for one of the given observations? observation 2 is a result of nitrate ions moving into the solution. observation 1 is a result of copper ions moving into the solution. observation 1 is a result of silver atoms losing one electron. observation 2 is a result of silver ions losing one electron.

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Question 1(multiple choice worth 4 points) (04.05 lc) what is the oxidation number of manganese in m...

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