If 64ᵃ⁺ᵇ = 32 ᵃ⁺²ᵇ, then a=?

64^(a+b)= 32^(a+2b)

<=>(2^6)^(a+b) = (2^5)^(a+2b)

<=>2^(6a+6b) = 2^(5a+10b)

=> 6a + 6b = 5a + 10b

=> a = 4b

Hope this helps!

:)

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!

d. all of the above

step-by-step explanation: