You are breeding two polyploid species of cabbage. you cross the two different species (parent 1 x parent 2) and obtain f1 hybrids. the following meiotic pairing was observed in the f1 hybrid: f1 hybrid = 9 bivalents + 9 univalents a) how many chromosomes are there in a non-dividing somatic cell of an f1 plant (i. e. what is the organisms ploidy)? b) how many chromosomes are there in a non-dividing somatic cell of each parent (i. e. what is the organisms ploidy)?

1) 36 chromosomes

2) Parent 1 = 24 chromosomes

   Non dividing somatic cells = 12 chromosomes

Explanation:

Given data:

F1 hybrid = 9 bivalents + 9 univalents

A. The plant that does not divide F1 has 12 univalents + 12 bivalents. It has 36 chromosomes in total.

Note: 1 bivalent chromosomes consist of 2 chromosomes

B. That parent's non-dividing somatic cell comprises 12 chromosomes, while the number is 24 for parent 1.

Parent 1 = 24 chromosomes

Non dividing somatic cells = 12 chromosomes

one is through turgidity. this occurs before ground tissue ( collenchyma

and sclerenchyma cells) become well

developed to give structural support to the plant as it grows bigger. the xylem

tissue (composed of rigid tissue) of the young

plant render this support and also maintaining osmotic turgidity of the surrounding

plant cells.

the diploid number of chromosomes is sometimes represented by the symbol 2n. for the fruit fly, the diploid number is 8, which can be written as 2n = 8, where n represents twice the number of chromosomes in a sperm or egg cell.