A coin is tossed four times. Assuming that the coin is equally likely to land on heads or tails, compute the probability of the event occurring. (Enter the probability as a fraction.)
At least two tails

Probability getting At least two tails is 11/15

Given that;

Coin tossed number of times = 4 times

Find:

Probability [At least two tails]

Computation:

Total number of toss = 2⁴

Total number of toss = 16

Number of chances less then two heads = 5

So,

At least two tails = 16 - 5

At least two tails = 11

Probability [At least two tails] = 11/15

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11/16

Explanation:

, HHHT,

HHTH, HTHH,

THHH, [HHTT,]

[HTHT], [HTTH],

[], [TTTH,]

[TTHT], [THTT]

[HTTT,] [TTHH,]

[THTH,] [THHT]

If we look at this, we see that there are 11 ways out of 16 in which we get at least 2 tails.

answer; overt behavior;