Write a function mymin that has two str parameters and returns the smallest. (Smallest in the sense of coming first alphabetically, not in the sense of "shortest".)

Complete Python code with explanation and output results is given below

Explanation:

A function named mymin is created which takes two arguments as input str_1 and str_2. Then using if else conditions compare them and return the smallest of them alphabetically.

To test the code, we called the function mymin three times with different inputs and each time the function mymin returned the correct values.

Python Code:

Function mymin:

def mymin(str_1,str_2):

   if str_1<str_2:

       return print("Smallest is:",str_1)

   else:

       return print("Smallest is:",str_2)

Test code:

mymin("Alpha","Beta")

mymin("Z","S")

mymin("Monday","Wednesday")

Output:

Smallest is: Alpha  

Smallest is: S  

Smallest is: Monday

(Alphabetically Alpha comes first than Beta)

(Alphabetically S comes first than Z)

(Alphabetically Monday comes first than Wednesday)

the median of the data is 4.

step-by-step explanation:

the median means the middle number of a given number.

to decide which one is the median, arrange in ascending or descending order. but sometimes, you may find two(2) number in the middle, but it's easy, just add them together and divide by 2.

so,   determine the median of the data. 2, 3, 3, 4, 5, 7, 9

it is already arranged, count 3 times forward and 3 backward and the one left is your answer.

2,3,3,4,5,7,9

our answer is 4.

hope this !