In chickens, rose comb (r) is dominant to single comb (r). a homozygous rose-combed rooster is mated with a single-combed hen. all of the chicks in the f1 generation were kept together as a group for several years. they were allowed to mate only within their own group. what is the expected phenotype of the f2 chicks?

25% Homozygous Rose Comb, 25% Homozygous Single Comb and 50% Heterozygous Rose Comb.

Explanation:

For a homozygous rose combed rooster (RR) and a homozygous single combed hen (rr), their first offspring F1 will be 100% heterozygous rose combed which has the genotype of Rr.

If the F1 generation are allowed to mate only among themselves, the second generation offspring, F2, will have 3 different genotypes which are homozygous rose comb (RR), homozygous single comb (rr) and heterozygous rose comb (Rr).

I hope this answer helps.

i think the answer is true : ))

the correct answer is "hematoma formation, with ligaments that are stretched, partially, of fully torn" ankle sprain are produced by an injury to the tough bands of tissue (ligaments) that surround and connect the bones of the leg to the foot. this causes several damage to the ankle including hematoma formation and ligament injury .