G(x) = ax2+24 for the function g defined above, a is a constant and g(4) = 8. what is the value of g(-4)?

So, Im assuming the x2 is x², if so then the answer would be

G(4)

Ax²+24=8

we replace the x with the value of 4 since we're given the answer

A(4)²+24=8

and then we try and solve the equation, first we need to get rid of the square which is (4)² thats the same as 4*4 thats equal to 16, so our equation would look like this

A(16)+24=8

then we carry on to try an look for (A), we can start by getting the difference between 24 and 8 so we move it to the other side as a -24 and get this

16 (A) = 8 - 24

which would basically be by adding a -24 to both sides so we can get rid of the +24, and we get the same equation as above

16(A)+24 -24 = 8 -24

16(A) = -16

then we need look for (A) by dividing both sides to 16

16(A)/16 = -16/16

and we get that (A) = -1

so with that now we can look for the value of G(-4)

first we form our new equation with the value of A and the new value of G which is -4, now since we are dealing with a square it doesnt matter if  (x) its positive or negative since it doesnt really affect the previous result (4)²=16 and (-4)²=16, but for the sake of it lets try to do it

G(-4)

A(-1)

ax²+24

so we replace with the values already obtained (A) and (x)

(-1)(-4)²+24

as stated before the

(-1)(16)+24

and all thats left is this

-16+24

and the answer to the question would be 8

is there multiple choice or do you need like an essay answer?