SAT, 04.08.2020 23:01 bandithcarroyuqhi

B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001 is a binary code word of length 4. The number of binary code words, B(n), of length n, is shown above. If the length is increased from n to n+1, how many more binary code words will there be? The answer is 2^n, but I don't get how they got that answer. I would think 2^n+1 minus 2^n would be 2. Please help me! Thank you!

Answers: 3

Show answers

Other questions on the subject: SAT

SAT, 26.06.2019 00:30, Sourcandy

Abag contains even and odd numbered balls in the ratio of 3: 7, respectively. for each of the following, what is the probability of drawing an even-numbered ball? the total number of balls is 240 and 30 of the odd-numbered balls are renumbered by multiplying the numbers by 4.

Answers: 1

continue

SAT, 26.06.2019 16:00, utjfkdndidndldn62121

Whats begin with t, ends with t has t in it

Answers: 2

continue

SAT, 27.06.2019 02:30, rebtav

Which will you likely have to provide on a college applications. a.) personal information, b.) parents level of education, c.) career plans, d.) employment history

Answers: 1

continue

SAT, 27.06.2019 14:00, EricaCox1

Jerrold has to buy 12 copies of a textbook which costs $36.25 per copy. how much must he spend for them?

Answers: 2

continue

You know the right answer?

B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001...