There are 15 animals in a barn. some are geese and some are buffalo. there are 56 legs in all. how many of each animal are there

Let  g= geese

b = buffalo

geese have 2 legs and buffalo have 4 legs

g+b = 15   the total number of animals

2g +4b = 56   the total number of legs

Multiply the first equation by -2

-2g -2b = -30

Add the second equation to eliminate g

-2g -2b = -30

2g +4b = 56

    2b = 26

Divide by 2

2b/2 = 26/2

 b = 13

There are 13 buffalo

g+b = 15

g+13 = 15

g =2

There are 2 geese and 13 buffalo

i think that the correct answer is

c. p equals 5,000 times, 0.3, to the power of the fraction m over 20