Awater skier is pulled behind a boat by a rope. the rope has a tension of 650 n and is at an angle of 27°. what is the y-component of the tension?

There is no figure, so I asume the angle of the rope is measured with respect to the horizontal direction.

If this is the case, then the magnitude of the tension is the hypothenuse of a right triangle, of which  and  (horizontal and vertical component of the tension) are the other sides, and  is the angle between T and . 
Therefore,  (the side of the triangle opposite to ) is given by the magnitude of the tension multiplied by the sine of the angle: