At what distance above the surface of the earth is the acceleration due to the earth's gravity 0.995 m/s2 if the acceleration due to gravity at the surface has magnitude 9.80 m/s2?

The distance above the surface of the earth is .

Explanation:

Given that,

Acceleration due to the gravity g'= 0.995 m/s² (at height )

Acceleration due to the gravity g= 9.80 m/s² (at surface )

We know that,

The formula of gravity at height

Where, h = height

r= radius of the earth

We substitute the value into the formula

Hence, The distance above the surface of the earth is .

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5