One skier covered the distance of 20 km 20 minutes faster than the other skier. find the speed of both skiers if one of them is travelling 2 km/hour faster than the other one.

Distance covered = 20 km
Let x km/h be the  speed pf first sky. Then, speed of second sky will be (x+2) km/h

Time = distance/speed

Therefore,

20/x - 20/(x+2) = 20 minutes = 1/3 hrs
Solving;
20(x+2) - 20(x)= x(x+2)*1/3
60(x+2) - 60(x) = x^2+2x
60x+120-60x =x^2+2x
120 = x^2+2x
x^2+2x-120 = 0

Then,
x = {-b+/- sqrt (b^2-4ac)}/2a = {-2+/- sqrt(2^2-4*a*-12)}/(2*1) = 10 or -12

Ignoring the negative value, x = 10 km/h

Therefore, the first sky is travelling at 10 km/h while  the  second is travelling at (10+2) 12 km/h