Amerry-go-round, with mass m and moment of inertia i, spins with angular speed ω on the earth’s equator. the merry-go-round’s surface is parallel to the earth’s surface with the y-axis oriented north and the x-axis oriented east. viewed from above the merrygo-round spins counter-clockwise, and viewed from above the north pole the earth rotates counter-clockwise. if tday is one day, and re is the earth’s radius, what is the total angular momentum of the merry-go-round about the center of the earth?

the assestment will probley apele with cause and effect

cant without the picture! ?

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.