Awell-insulated rigid tank having a volume of 0.25 m3 contains saturated water vapor at 100ᴼc. the water is rapidly stirred until the pressure is 1.5 bars. determine the temperature at the final state, in ᴼc, and the work during the process, in kj.

State 1:
From steam tables;
T1 = 100°C
P1 = 1.01325 Bar
S1=Sg = 7.355 kJ/kg.K

State 2:
P= 1.5 Bar
T2 = ?

This point is super-heated but entropies should be equal.

S1=Sg=S2 = 7.355 kJ/kg.K

This point lies between saturation point at 1.5 Bar and 150 °C super-heat state. By interpolation,
T2 = 111.4+ (7.355-7.223)/(7.420-7.223)*(150-111.2) = 137.26 °C

Work done:

W=ΔU = m(u2-u1)
u1= 2506 kJ/kg
u2 = 2519 + (7.355-7.223)/(7.420-7.223)(2580-2519) = 2559.87 kJ/kg
m= volume/specific volume, where specific volume = 1.159+(7.355-7.223)/(7.420-7.223)(1.286-1.159) = 1.244 m^3/kg

Then, m=0.25/1.244 = 0.2 kg

Therefore,

W= 0.2*(2559.87-2506) = 10.77 kJ

Cin carbonh in hydrogeno in oxygen

There is no graph to look at on here, but i shall explain them to you. a line graph is just in its title it’s a graph with a line running through the dots to show an increase or decrease. a bar graph is used to show how much or how little something is so a comparison. a scatter plot is used to graph points to tell the data. and i don’t know what a histogram is.