Janet wants to find the spring constant of a given spring, so she hangs the spring vertically and attaches a 0.47 kg mass to the spring's other end. if the spring stretches 3.1 cm from its equilibrium position, what is the spring constant? 133 incorrect: your answer is incorrect. n/m

The force needed to extend or compress a spring is directly proportion to the applied stress in spring. The spring constant of a given spring is 148.71 N/m.

The Hook's law:

Within the elastic limit the force needed to extend or compress a spring is directly proportion to the applied stress in spring.

The force applied by the wight

Where,

m = mass = 0.47 kg

g - gravitational acceleration =

Put the values in the equation,

Spring constant can be calculated using the Hook's law,

Therefore, the spring constant of a given spring is 148.71 N/m.

To know more about Hook's law,

link

  148.6 N/m

Explanation:

The 0.47 kg mass applies a force of ...

   F = ma = (0.47 kg)(9.8 m/s^2) = 4.606 N

which stretches the spring by 3.1 cm, or 0.031 m. That means the spring constant is ...

  (4.606 N)/(0.031 m) ≈ 148.6 N/m

Additional comment

The supplied numbers have 2 significant figures. If the spring constant is rounded to 2 significant figures, it would be 150 N/m.

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