A1.0 104 kg spacecraft is traveling through space with a speed of 1200 m/s relative to earth. a thruster fires for 2.0 min, exerting a continuous force of 25 kn on the spacecraft in a direction opposite the spacecraft’s motion. calculate the initial momentum and the final momentum of the spacecraft.

We are given information:


If we apply Newton's second law we can calculate acceleration:
F = m * a
a = F / m
a = 25000 / 10000
a = 2.5 m/s^2

Now we can use this information to calculate change of speed.
a = v / t
v = a * t
v = 2.5 * 120
v = 300 m/s

Force is being applied in direction that is opposite to a direction in which space craft is moving. This means that final speed will be reduced.
v = 1200 - 300
v = 900 m/s

Formula for momentum is:
p = m * v
Initial momentum:
p = 10000 * 1200
p = 12 000 000
p = 12 *10^6 kg*m/s
Final momentum:
p = 10000 * 900
p = 9 000 000
p = 9 *10^6 kg*m/s

When is this

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