If a heater took 4 minutes to convert 500g of liquid water to 500g of water vapour how long would the same heater take to convert 500g of liquid aluminium to 500g of aluminium gas

t₁ = time to convert liquid water to water vapor = 4 min = 4 x 60 = 240 sec

t₂ = time to convert liquid aluminium to aluminium gas = 4 min = ?

m₁ = mass of water = 500 g = 0.5 kg

L₁ = latent of vaporization = 2260000 J/kg

m₂ = mass of aluminium = 500 g = 0.5 kg

L₂ = latent of vaporization of aluminium = 10530000 J/kg

using conservation of heat

m₁ L₁ /t₁ = m₂ L₂ /t₂

(0.5) (2260000)/240 = (0.5) (10530000)/t₂

t₂ = 1118.23 sec

t₂ = 18.6 min

its a 5.5 n

glad that

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min