Determine the quantity of work done when a crane lifts a 100-n and block from 2 m above the ground to a 6 m above the ground

400 J

Explanation :

Given that,

Force = 100 N

Distance  = 6 m - 2 m = 4 m

Now , the work done is equal to the multiplication of the force and distance.

W = F * d

Hence, the quantity of work done is 400 J

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j