Calculate the average power required to lift a 490-newton object a vertical distance of 2.0 meters in 10. seconds. [show all work, including the equation and substitution with units.]

For this problem, you should be able to differentiate the variables presented from each other in order to substitute them in their corresponding places in the formula or formulas to be utilized in this problem. As for this problem, the only formula to be utilized would be the formula for power which is force multiplied to distance over time or simply have force multiplied to speed since speed is equal to distance over time.

The formula would like this:

Power = force x distance / time                          Power = force x speed

P = 490 N x 2 m / 10 s                                        P = 490 N x (2 m / 10 s)
P = 980 N m / 10 s                                              P = 490 N x 0.2 m / s
P = 98 W                                                             P = 98 W

So the average power required to lift a 490-newton object a vertical distance of 2.0 meters in 10 seconds would be 98 watts.

    5.5 n======    assuming that      we have      m = 0.145 kg    a = 38 m/s²therefore    5.51 n, but two significant figures.final answer: 5.5 n