Physics, 29.07.2019 21:30 ninaaforever

Suppose you charge a 1.0 f capacitor with two 1.5 volt batteries. how much charge was on each plate?

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Answer from: ericsmith19

If you charge a 1.0 f capacitor with two 1.5 volt batteries, the amount of charge on each of the plates is 3colombs

The formula for calculating the charge on a capacitor is expressed as:

$Q = C \triangle v$

C is the capacitance of the capacitor in farads

Δv is the change in the potential difference

Given the following parameters

C = 1.0F

For a two 1.5V batteries, v = 2(1.5) = 3V

Substitute the given parameters into the formula as shown:

$Q = 1.0 \times 2(1.5)\\Q=1 \times 3.0\\Q =3Coulumbs$

Hence the amount of charge on each of the plates is 3colombs.

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Answer from: asims13

The charge on each plate of the capacitor is given by:
$Q=C \Delta V$
where C is the capacitance of the capacitor, while $\Delta V$ is the potential difference applied on the two plates. Since we are using two batteries of 1.5 V, the total voltage applied is (assuming the two batteries are in series) 1.5 V+1.5 V= 3.0 V. Therefore, the charge on each plate is
Q=(1.0 F)(3.0 V)=3.0 C

Answer from: Quest

i don't understand. explain it clearly

Answer from: Quest

m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| = √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| = √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| = 14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

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