Aball is released from a hot air balloon moving downward with a velocity of -10.0 meters/second and a height of 1,000 meters. how long did it take the ball to reach the surface of earth? given: g = -9.8 meters/second2. 11.2 seconds 12.1 seconds 13.3 seconds 13.5 seconds 14.2 seconds

We will be using the equation S = ut + 1/2 g t^2
Given S = -1000 m, u = -10 m/s and g = -9.8 m/s^2 
Plugging in the information given above, 1000 = 10t + 4.9 t^2 
We have a quadratic equation in t as 4.9t^2 + 10t -1000 = 0 t=−b±√b2−4ac / 2a
t=−(10)±√(10)2−4(4.9)(−1000) / 2(4.9)
t= −10±√19700/ 9.8
t=13.301702905732856,
so solving we get t = 13.3 s.

This is kenetic energy.