Physics, 01.09.2019 11:00 Neishab932

Astudent conducted an experiment to measure the acceleration due to gravity 'g' of a simple pendulum.
length of thread , l/m : 0.35
time for 20 oscillations, t/s : 24.1
length of thread, l/m : 0.65
time for 20 oscillations : 3.24
length of thread, l/m : 1.00
time for 20 oscillations : 4.01
lenght of thread, l/m : 1.45
time for 20 oscillations : 47.5
length of thread : 1.95
time for 20 oscillations : 56.3
given that the realtion between the period 't', the length of the pendulum 'l' and the acceleration due to gravity 'g' is t=2(pi)√(l/g), find the value of 'g'.

Answers: 1

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