What is the ratio of orbital velocity to escape velocity

Orbital velocity is the velocity of celestial body/satellite revolving around another celestial body in circular orbit. 
V =  ---(i)

Escape velocity is the minimum initial velocity a body should be given to escape it from gravitational field.
V =  ---- (ii)

Divide (i) and (ii)



R = radius of circular orbit, M = mass of the celestial body about which satellite/body is performing circular motion. G = Universal gravitational constant 

0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2

Iassume the answer is 75 feet. inwards to outwards rather than outwards to inwards. probably be 75.hachures are stokes drawn in direction of the steepest slope. a series of short parallel lines drawn on a map to indicate topographic relief. it is actually called hachures on contour lines. the small marks in the center of the feature are called hachures.observe the picture attached