Calculate the orbital period for jupiter's moon io, which orbits 4.22×105km from the planet's center (m=1.9×1027kg) .

150000 seconds or approximately 1.7 days. The equation for the orbital period is: Ď„=âš((4Ď€^2/ÎĽ)a^3) where Ď„ = Period ÎĽ = standard gravitational parameter (GM) a = semi-major axis It's generally better to use ÎĽ rather than the product of G and M since we know ÎĽ more accurately than either G or M in many cases from observations of satellites around the various planets. For instance in the case of Jupiter, we know ÎĽ is 1.26686534(9)Ă—10^17 whereas we only know it's mass at 1.8982x10^27 kg and G at 6.674x10^-11 m^3/(kg*s^2). Anyway, let's first calculate ÎĽ based upon the data given: ÎĽ = 1.9x10^27 kg * 6.67ex10^-11 m^3/(kg*s^2) ÎĽ = 1.26806x10^17 m^3/s^2 Now let's substitute the known values into the equation for the orbital period. Ď„=âš((4Ď€^2/ÎĽ)a^3) Ď„=âš((4Ď€^2/1.26806x10^17)(4.22x10^8)^3) Ď„=âš((4*9.869604401/1.26806x10^17)(7.5151448x10^25) Ď„=âš((39.4784176/1.26806x10^17)(7.5151448x10^25) Ď„=âš((3.11329256x10^-16)(7.5151448x10^25) Ď„=âš(2.3396844x10^10) Ď„=152960.2706 Rounding to 2 significant figures since that's the precision of the least accurate datum, we get 150000 seconds, or approximately 1.7 days.

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Is there any opitions? if you have the periodic table, the noble gases are 8a family, the halogen are the 7a family, and the nonmetal are  carbon, nitrogen, phosphorus, oxygen, sulfur, selenium, fluorine, chlorine, bromine, iodine and astatine.