Photon has a frequency of 7.3 × 10–17 hz. planck’s constant is 6.63 × 10–34 j•s. the energy of the photon, to the nearest tenths place, is × 10–50 j.

The energy of the photon can be calculated using one of the following two rules:
Rule 1: E = hf where h is Planck's constant and f is the frequency
Rule 2: E = (hc) / lambda where h is Planck's constant, c is the speed of light and lambda is the wavelength.

We are given that:
Planck's constant (h) = 6.63 * 10^-34 Js
frequency (f) = 7.3 * 10^-17 Hz

Based on these givens, we will use Rule 1.
Substitute with the givens in Rule 1 to get the energy as follows:
E = hf
E = 6.63 * 10^-34 * 7.3 * 10^-17
E = 4.8 * 10^-50 Joules

Distance^2= yellow line ^2 (see picture) = 30^2 + 49^2so distance = squareroot of (300^2 +49^2)i dont know if this is how to solve it, but i cnt think of another way