If you go outside on a hot summer day with a double scoop ice cream cone, how will the cold ice cream interact with the hot outside air?

The ice cream and the air are at a different temperature, the air temperature being higher than the ice cream temperature.

Due to this difference, the air and ice cream will tend to reach a state of equilibrium by transferring energy in the form of heat, which flows from the system with a higher temperature to the system with a lower temperature.

So the hot air will transfer heat to the ice cream, which will increase its temperature and will make it liquid, so the ice cream will eventually melt.

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete

volts times amps 6 x 0.5 3w