Find the moment of inertia about an axis that passes through mass a and is perpendicular to the page.

Let … A --> 1 … B --> 2 … C --> 3 … then … … m₠= 200 g … m₂ = 100 g … m₠= 100 g … so that … m₠+ m₂ + m₠= 400 g … moreover … … ( x₂ , y₂ ) = ( 0 , 0 ) = coordinates of m₂ … … ( x₠, y₠) = ( 12 cm , 0 ) = coordinates of m₠… … x₠= ½ ( 12 cm ) = 6 cm … x₠² + y₠² = ( 10 cm ) ² … … y₠= ⚠[ ( 10 cm ) ² - x₠² ] = ⚠[ 64 cm ] = 8 cm … … ( x₠, y₠) = ( 6 cm , 8 cm ) = coordinates of m₠… … Xcm = ( m₠x₠+ m₂ x₂ + m₠x₠) / ( m₠+ m₂ + m₠) … … Ycm = ( m₠y₠+ m₂ y₂ + m₠y₠) / ( m₠+ m₂ + m₠) … … Ia = m₂ r₂ ² + m₠r₠² … r₂ = r₠= 10 cm … … Ibc = m₠y₠²

Idon't know it i just need my points lol