If the blocks are released from rest, which way does the 10 kg block slide, and what is its acceleration? enter a positive value if 10 kg block accelerates up the rump, and a negative value otherwise.

Suppose that θ=35∘

First, you need to set up equations for both blocks.

Let m1 be 10kg and m2 be 5kg and for our computations suppose right is positive and up is positive

For m1 the solution is:
Sigma Fx = ma 
T - m1gsin35 = m1a where T = tension 

For m2 
m2g - T = m2a 

Add the two equations together 

m1a + m2a = T-m1gsin35 + m2g - T 
a(m1 + m2) = m2g - m1gsin35 
a= (5*9.8 - 10*9.8*sin35)/(10 + 5) 
a= -0.48m/s/s 

6/12=1/2

step-by-step explanation:

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