Atruck with a heavy load has a total mass of 9100 kg. it is climbing a 15â incline at a steady 15 m/s when, unfortunately, the poorly secured load falls off! immediately after losing the load, the truck begins to accelerate at 1.5 m/s2.

Our answer is 3380kg

Explanation:

The force required to move the truck at constant speed in the given case is.

F=Mg sin∅ =(9100kg)(9.8m/s²)sin15° =2.31×10⁴ N

The net force on the truck after the mass is fell down from the truck is

Fnet =F- mg sin∅

ma= F-mg sin∅

m(1.5m/s²) =( 2.31 × 10⁴N) -m(9.8m/s²)sin 15°

Solve for m.

m((1.5m/s²) +(9.8m/s²)sin 15°) =(2.31 ×10⁴ N))

m = 5720kg

Mass of load is.

Δm =M -m =(9100kg) -(5720kg) =3380kg

c. newton's third law of motion

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.