Aforce of 160. n parallel to an inclined plane is required to move a 200. n weight up the inclined plane with a constant velocity. find the coefficient of sliding friction if the plane is inclined at 30.0 degrees.

- Drawing a free body diagram will help you visualize the different forces acting on an object.

- Find ∑Fy and ∑Fx and solve for unknowns; force due to kinetic friction (fk) and normal force (Fn).

- After solving for unknowns, plug values into equation for kinetic friction, fk = μk • Fn, and solve for μk

Coefficient of kinetic/sliding friction = .3464

See attached photo for worked out solution.

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

Because the sun is the biggest and if the sun orbits the earth we will be dead probably