Atrain is slowing down with an average acceleration of −5.0 m/s2 (negative sign shows deceleration). if its initial velocity is 50. m/s, how far does it travel in 6.0 seconds?

This problem requires 2 kinematics equations. What you first must do is find the Final Velocity with the given values... Vf = Vi + at ... which is Vf = 50 + (-5)(6) which would simplify to Vf = 30. Then you can plug this value along with the given values into the kinematics equation Vf^2=Vi^2 + 2ax. Plugged in this would be 30^2=50^2 + 2 (-5)x. This can then be simplified to find x (distance). Which would be x=160. This means that the train traveled 160m.

Is a  vector quantity  that refers to "the rate at which an object changes its position." imagine a person moving rapidly - one step forward and one step back - always returning to the original starting position. while this might result in a frenzy of activity, it would result in a zero velocity. because the person always returns to the original position, the motion would never result in a change in position. since velocity is defined as the rate at which the position changes, this motion results in zero velocity. if a person in motion wishes to maximize their velocity, then that person must make every effort to maximize the amount that they are displaced from their original position. every step must go into moving that person further from where he or she started. for certain, the person should never change directions and begin to return to the starting position.

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