Atoy balloon is initially at a temperature of t = 20o c. its initial volume is 0.0042 m3 (it is a 10 cm radius sphere). assume that the pressure in the balloon always equals atmospheric pressure, 101.3 kpa. 1) the balloon is lying in the sun, which causes the volume to expand by 6%. what is the new temperature, t? t =

37.589C For gas laws, temperatures must be converted to Kelvin: 20C + 273.15 = 293.15K The balloon assures that the mass of the gas remains the same and the problem states that the pressure of the gas remains the same. This means that a 6% change in volume corresponds to a 6% change in temperature. From this we calculate 293.15K * 1.06 = 310.739K converting back to C 310.739 - 273.15 = 37.589C

So what is the question