Acomputer is reading data from a rotating cd-rom. at a point that is 0.040 m from the center of the disc, the centripetal acceleration is 114 m/s2. what is the centripetal acceleration at a point that is 0.058 m from the center of the disc?

165 m/s^2 The formula for centripetal acceleration is F = v^2/r where F = force v = velocity r = radius v = 2 pi a r where a = angular velocity r = radius Now we're increasing r by a factor of 0.058/0.040 = 1.45 So v increases by a factor of 1.45 So v^2 increases by 1.45^2 But r in the divisor also increases by a factor of 1.45, so the overall increase in force is 1.45^2/1.45 = 1.45 So just multiply the force experienced at 0.040 m by 1.45 0.040 * 1.45 = 165.3 m/s^2