Astone is dropped from a cliff. after it has fallen 10m what is the stones velocity

V=14,1421 m/s

Explanation:

it's simple.

Velocity increases with the gravity acceleration.

There's a formula called Torricelli's equation, and it is as it follows:

V^2 = Vo^2 +2.a.s

where V is the speed you wish to find

Vo is the initial speed

a is the acceleration, in this case, the gravity's one

s is the space it moved.

So, here we go

Vo=0

a=10 or 9.81 (some schools use 10 to simplify the math)

s=10

So, using g as 10

V^2 = 0 +2.10.10

V^2=200

V=14,1421 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s